1. Ammeter current = 0.3A,
Cell voltage = 9V, Resistance of bulb = 

2. Voltage
of battery = 9V, Resistance
of buzzer = 50 Ohms, Current
= 0.05A Resistance
of the motor =


3.
When
switch is closed: p.d across bulb Y = 5V, Resistance of bulb Y = 400
Ohms, Resistance of bulb X = 500 Ohms,
P.d.
across bulb X =


4.
When
switch is closed: Current flowing through circuit = 0.05A, Resistance of bulb
X = 2 kilo Ohms, P.d.
across bulb Y = 130V
Voltage
of supply =


5.
Current flowing out of cell = 2.5A, Current flowing into top bulb is 0.5A,
Resistance of top bulb = 10 Ohms
Resistance
of lower bulb is

